zipWith
Combines multiple arrays into a single array using a custom combiner function.
This function takes multiple arrays and a combiner function, and returns a new array where each element is the result of applying the combiner function to the corresponding elements of the input arrays.
Signature
typescript
function zipWith<T, R>(arr1: T[], combine: (item: T) => R): R[];
function zipWith<T, U, R>(arr1: T[], arr2: U[], combine: (item1: T, item2: U) => R): R[];
function zipWith<T, U, V, R>(arr1: T[], arr2: U[], arr3: V[], combine: (item1: T, item2: U, item3: V) => R): R[];
function zipWith<T, U, V, W, R>(
arr1: T[],
arr2: U[],
arr3: V[],
arr4: W[],
combine: (item1: T, item2: U, item3: V, item4: W) => R
): R[];
Parameters
arr1
(T[]
): The first array to zip.arr2
(U[]
, optional): The second array to zip.arr3
(V[]
, optional): The third array to zip.arr4
(W[]
, optional): The fourth array to zip.combine
((item1: T, item2: U, item3: V, item4: W) => R
): The combiner function that takes corresponding elements from each array and returns a single value.
Returns
(R[]
): A new array where each element is the result of applying the combiner function to the corresponding elements of the input arrays.
Examples
typescript
// Example usage with two arrays:
const arr1 = [1, 2, 3];
const arr2 = [4, 5, 6];
const result = zipWith(arr1, arr2, (a, b) => a + b);
// result will be [5, 7, 9]
// Example usage with three arrays:
const arr1 = [1, 2];
const arr2 = [3, 4];
const arr3 = [5, 6];
const result = zipWith(arr1, arr2, arr3, (a, b, c) => `${a}${b}${c}`);
// result will be ['135', '246']